The average of four numbers is 90. Two of the numbers are equal (not least), and 40 more than the least number. If the 4th number is five times the least number then find the average of smallest and largest number.
ATQ, Let the two equal numbers be ‘e’ each Therefore, least number = (e – 40) 4th number = 5(e – 40) According to the question, 5(e – 40) + e – 40 + e + e = 4 × 90 Or, 8e – 240 = 360 Or, e = 600/8 = 75 Therefore, 4 numbers are 75, 75, 35, and 175 Therefore, required average = (175 + 35)/2 = 105
74% of 2840 + 80% of 1640 - ?= 47²
What will come in place of the question mark (?) in the following question?
24.30% of 372.32 = ?
25.6% of 250 + √? = 119
182 – 517 ÷ 11 - √361 = ?
1365 ÷ 15 + (? ÷ 5) = 62 × 3.5
The alarms of two alarm clocks sound at regular intervals of 72 seconds and 80 seconds. If they beep together for the first time at 6:00 am, at what tim...
(168 ÷ 12 + 19 × 64)/(22+1)
33 + (6.25) % of 1600 = ? + 2 X 55
[4(1/3) + 4(1/4)] × 24 – 62 = ?2
