ATQ, Let the two equal numbers be ‘e’ each Therefore, least number = (e – 40) 4th number = 5(e – 40) According to the question, 5(e – 40) + e – 40 + e + e = 4 × 90 Or, 8e – 240 = 360 Or, e = 600/8 = 75 Therefore, 4 numbers are 75, 75, 35, and 175 Therefore, required average = (175 + 35)/2 = 105
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