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ATQ, Let the average height of a person in group 'J' = 'b' cm. Then, the average height of a person in group 'I' = (b - 18) cm. Total height of all people in group 'J' = 30 × b = '30b' cm. Total height of all people in group 'I' = 36 × (b - 18) = 36b - 648 cm. So, 36b - 648 = 30b. Or, 6b = 648. So, b = 648 / 6 = 108. Required average height = 108 cm.
The value of the expression (1 + sec22° + cot68°)(1 – cosec22° + tan68°) is
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The value of x which satisfies the equation (x+a2+2c2) / (b+c) + (x+b2 +2a2) / (c+a) + (x+c+2b2) ...
If a + 1/a = -2 then the value of a1000 + a- 1000 is
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The simple interest accrued on a sum at the rate of 10% p.a. for two years is Rs. 5,000.
Quantity I – What will be the compound interest o...
If 2cos2 Ɵ – 5cos Ɵ + 2 = 0,00 < Ɵ < 900 , then the value of (cosec Ɵ + cot Ɵ) is :
10 women and 12 men complete a certain piece of work in 30 days, if each women takes thrice the time taken by a man to finish the work.
Quanti...
If (a + b)/c = 6/5 and (b + c)/a = 9/2, then what is the value of (a + c)/b?
If 0 ≤ θ ≤ 90°, and sec107 θ + cos107 θ = 2, then. (secθ + cosθ) is equal to:
