Question
The average height of each person in group 'K' having 22
people is 14 cm less than the average height of each person in group 'L' having 18 people. If the sum of the heights of all people in group 'K' is the same as that in group 'L', then what is the average height of a person in group 'L'?Solution
ATQ, Let the average height of a person in group 'L' = 'c' cm. Then, the average height of a person in group 'K' = (c - 14) cm. Total height of all people in group 'L' = 18 × c = '18c' cm. Total height of all people in group 'K' = 22 × (c - 14) = 22c - 308 cm. So, 22c - 308 = 18c. Or, 4c = 308. So, c = 308 / 4 = 77. Required average height = 77 cm.
(i) x² – 3x – 40 = 0
(ii) y² + 11y + 30 = 0
I. 35x² - 51x + 18 = 0
II. 30y² + 17y – 21 = 0
Equation 1: x² - 200x + 9600 = 0
Equation 2: y² - 190y + 9025 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. x2 + 25x + 154 = 0
II. y2 + 27y + 181 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. 3x² –7x + 4 = 0�...
I: x2 - 33x + 242 = 0
II: y2 - 4y - 77 = 0
I. 15y2 + 26y + 8 = 0
II. 20x2 + 7x – 6 = 0
I. √(17x) + √51 = 0
II. √(4y) + 3 = 0
I. 27(p + 2) = 2p(24 – p)
II. 2q2 – 25q + 78 = 0
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