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Let number of students be 'N' and sum of marks of all the students be 'S'. ATQ: We have, [(S - 80 + 40) /N] = (S/N) - 2 Or, (S/N) - [(S - 40) /N] = 2 Or, (40/N) = 2 So, 'N' = (40/2) = 20 Therefore, total number of students are 20.
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Statement...
If log 2 = 0.3210 and log 3 = 0.4661, the value of log5 1024 is:
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