ATQ,
Time taken to return to his residence = (50/20) = 2.5 hours Total distance = 2 × 50 = 100 km Total time = 3.5 + 2.5 = 6 hours Average speed = (100/6) = 16.67 km/h
Alternate Solution: Speed while going to the friend’s house = (50/3.5) = 14.29 km/h Required average speed = {(2 × 14.29 × 20)/(14.29 + 20)} = (571.6/34.29) = 16.67 km/h
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