Consider six consecutive odd numbers whose average is 34. If the highest number from this set is removed, what will be the average of the remaining five numbers?
Let six consecutive odd numbers be ‘x’, ‘x + 2’, ‘x + 4’, ‘x + 6’, ‘x + 8’, ‘x + 10’, respectively. ATQ; (x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10) = 34 × 6 Or, 6x + 30 = 204 Or, 6x = 174 Or, x = 29 When, the greatest number is excluded, Then, new sum of the remaining five numbers = x + x + 2 + x + 4 + x + 6 + x + 8 = 5x + 20 Required Average = {(5x + 20)/5} = (x + 4) = 29 + 4 = 33
74% of 2840 + 80% of 1640 - ?= 47²
What will come in place of the question mark (?) in the following question?
24.30% of 372.32 = ?
25.6% of 250 + √? = 119
182 – 517 ÷ 11 - √361 = ?
1365 ÷ 15 + (? ÷ 5) = 62 × 3.5
The alarms of two alarm clocks sound at regular intervals of 72 seconds and 80 seconds. If they beep together for the first time at 6:00 am, at what tim...
(168 ÷ 12 + 19 × 64)/(22+1)
33 + (6.25) % of 1600 = ? + 2 X 55
[4(1/3) + 4(1/4)] × 24 – 62 = ?2
