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Total marks of five students = 24 X 5 = 120 Total marks of seven students = (22 X 7) = 154 Required sum = (154 - 120) = 34 Hence, option b.
(155.34 + 234.78) ÷ 12.65 = ? ÷ 4.99
16.01(? × 8.09 ÷ 16.09) = 3.01 of 69.69 + 14.12 of 4.01 - 100.998 of 2.19
116.90 ÷ (77.81 ÷ 6.06) + 6.32 = (15.12% of ?) ÷ 4.652
? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09)
[(343) 1/3 ÷ {(12.001)2 × (1 ÷ (4.03 × 2.97) 2 )}] = ?
25.11% of 239.99 + √143.97 ÷ 12.02 = ?
(6859.01)1/3 × 10.11 × 14.47 ÷ 20.32 = ? + 45.022
(56.03 + 112.98) ÷ 13.211 = 89.9 – 25.23% of ?
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76