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ATQ, Let number of teachers in Department B = ‘x’ Number of teachers in Department A = 1.80 × x = 1.8x So, 1.8x + x = 112 Or, 2.8x = 112 Or, x = 40 Number of teachers in Department B = 40 Number of teachers in Department A = 1.8 × 40 = 72 Let average weight of teachers of Department B = ‘y’ kg Average weight of teachers of Department A = 1.40 × y = 1.4y kg According to question; (40 × y + 1.4y × 72)/112 = 88 Or, 40y + 100.8y = 88 × 112 Or, 140.8y = 88 × 112 So, y = 70 Average weight of teachers in Department A = 1.4y = 1.4 x 70 = 98 kg
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