ATQ,
From the equations derived: A+B+C=90 C+D+E=57 A+E=46 B+E=48 We expressed everything in terms of A: E=46−A B=2+A C=88−2A D=3A−77 However, no unique value of A is determined from these equations because the system of equations is under determined. There are more variables (A,B,C,D,E) than independent equations. This means multiple sets of values can satisfy the equations, making it impossible to uniquely determine B. Thus, the answer is indeed "cannot be determined."
? = 500.24 + 1013.97 – 7.992
29.88% of 3599.90 + 5/12 of 2399.81 – 34.81% of 1200.18 = ?
16.98 × 88.05 + 1999.996% of 299.08 + 5.005 % of 4999.997 = ? × 20.98 × 40.009
15.1 + 3.97 – 9.07 × 1.96 = √?
? 3 + 95.06 X 39.87 ÷ 5.03 = 1271.89
√81.02 + 11.836 of 24.98 = ?2 + 20.01
440.11 ÷ 21.98 × 5.14 – 72.9 = √?
1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 × 9.05 = ?
(1550.23 ÷ 30.98) + (864.32 ÷ 23.9) + 1724.11 = ?
1080.04 – 330.18 + 449.98 ÷ 15.06 = ?