ATQ,Total weight of all the employees = (52 × 38) = 1976 kg Total weight of the all the person in the office including the manager = (53 × 38.2) = 2024.6 kg Therefore, the weight of the manager = 48.6 kg Alternate Solution Required weight of the class teacher = {(53 × 200)/1000} + 38 = 48.6 kg
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