Question
The mean of five two-digit
numbers is 34. Among these five numbers, two are 'P' and 'Q'. If the digits of both 'P' and 'Q' are swapped, the new mean of the five numbers changes to 14.2. Alternatively, if the other three numbers (excluding 'P' and 'Q') are multiplied by '−1', the mean of the five numbers becomes 10. What is the sum of the tens digits of 'P' and 'Q'?Solution
ATQ,
Let, P = 10a + b, Q = 10c + d & Sum of other 3 numbers = R Given P + Q + R = 34 × 5 = 170 --- (1) P + Q – R = 10 × 5 = 50 --- (2) Solving equation 1 & 2, we have, P + Q = (170 + 50)/2 = 110, So, R = 170 – 110 = 60 & (10a + b) + (10c + d) = 110 (b + d) = 110 – 10(a + c) --- (3) Again, given that, (10b + a) + (10d + c) + R = 5 × 14.2 (10b + a) + (10d + c) + 60 = 71 (10b + a) + (10d + c) = 11 10(b + d) + (a + c) = 11 10[110 – 10(a + c)] + (a + c) = 11 1100 – 100(a + c) + (a + c) = 11 99(a + c) = 1089 (a + c) = 11 = Sum of tens digit
Statements: M $ K; K & N, N % R, R @ W
Conclusions:Â Â Â Â Â
I. W & KÂ Â Â Â Â Â Â Â
II. K & WÂ Â Â Â Â Â Â Â Â Â Â Â ...
I n the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and t...
Statements: I % C, C & D, D $ K, K # Z
Conclusions: I. I & DÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. D # Z
...Statements: P ≤ Q > R > T > U, Q ≤ O < S, T < V
Conclusions:
I. R < S
II. P > U
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is/are definitely true and th...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is/are definitely true and the...
Statements: H < I; J < L < K; H ≥ L > M
Conclusions:
I. J < I
II. M < K
III. K > I
Statements: A ≤ B > C ≥ D > F, B ≤ E > G, D < H
Conclusions: I. G ≥ A
II. H > F
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and t...
Statement: A≤B ≤C>D ; E<D ;F>E
Conclusions:
I. D>A
II. E<C
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