ATQ; Let the three numbers be x, y, and z.So,2x+y+z=350×2=700x+2y+z=330×2=660x+y+2z=310×2=620Thus,4×(x+y+z)=1980x+y+z=495Now,x=700−495=205y=660−495=165z=620−495=125Desired difference = 205−125=80
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