A bowler gives 15.2 runs per wicket. He gives 32 runs and takes 4 wickets in the last match after which his average becomes 14.4 runs per wicket. How many wickets have been taken by him before the last match?
Bowling average = (Total run conceded)/(Total wicket taken) Let the total number of wickets be x Then, bowling average = 15.2 Runs conceded = 15.2x Now, (15.2x+32)/(x+4) = 14.4 15.2x + 32 = 14.4 (x + 4) 15.2x + 32 = 14.4x + 57.6 0.8 x = 57.6 – 32 x = 25.6/0.8 = 32
LCM of 21 5 , 21 10 and 21 15 is?
(1). 21 5
(2). 21 15
(3).2130
LCM of two numbers is 5 times their HCF. The product of the numbers is 4500. What will be the maximum possible difference between the numbers?
What is the least number which when divided by 3, 15 & 18 leave a remainder 6 in each case & it is also divisible by 12?
The HCF of two numbers 110 and 1980 is:
A number is three times another number and their HCF is 8. What is the sum of the squares of the numbers?
Three boys runs around a circular track and takes 20 min, 25 min and 30 min respectively to complete the one round. When do they all come relatively to ...
How many pairs of natural numbers (x, y) exist such that x>y and the product of x, y and HCF (x, y) = 2520? solve this
The H.C.F of two numbers is 2 and their L.C.M is 117. If one of the numbers is 13, find the other?