OA = distance covered by upstream speed in 12 minutes = 12/60 (x – y ) OB = distance covered by downstream speed in 12 minutes = 12/60 (x + y ) According to the question, OB – OA = AB 12/60 (x + y ) - 12/60 (x - y ) = 200/1000 1/5 (x + y - x + y) = 200/1000 2y = 2/10 × 5 y = 0.5 km/hr. Speed of current = 0.5 km/hr.
25.11% of 199.99 + √143.97 ÷ 6.02 = ?
30.11% of 149.99 + √195.97 ÷ 7.02 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
24.01 X 24.99 - ?% of 599.96 = 14.92 X 8.12
(804/65) ÷ (11/798) × (129/131) = ?
11.11% of (123.45 + 234.56) + 10.01³ - (5.05 of 7.07) = ? of (88.88 - 33.33)
What will be the approximate value of the following questions.
(1/2 of 959.90 + 69.69% of 359.79) ÷ (√63.94 × 2/5 of 250.14) = ?
12.5% of 6400 + (17 × 25) = ?% of 2200+ 125
22.03 × 6.97 + 19.01 – 16.02 = ?
