A swimmer swims from a point A against a current for 12 minutes and then swims backwards in favour of the current fornext 12 minutes and comes to the point B. If AB is 200 metres, the speed of current (in km per hour) is
OA = distance covered by upstream speed in 12 minutes = 12/60 (x – y ) OB = distance covered by downstream speed in 12 minutes = 12/60 (x + y ) According to the question, OB – OA = AB 12/60 (x + y ) - 12/60 (x - y ) = 200/1000 1/5 (x + y - x + y) = 200/1000 2y = 2/10 × 5 y = 0.5 km/hr. Speed of current = 0.5 km/hr.
Glyoxysomes, a cell organelle where glyoxylate cycle occurs is present in
The deltas of Mahanadi and Godavari are rich in
What characterizes facultative parasites, and how do they differ from obligate parasites?
In functional foods,prebiotics are
The method of monitoring the nutritional status of plants by periodic and regular sampling and analysis of soil and plant parts is known as:
...Monocropping of tobacco is always discouraged as
A. it leads to the development of Pest and disease complex
B. it decreases soil fertility...
What are tyloses, and what is their role in plant defense against pathogens?
What is the purpose of callus initiation in plant tissue culture?
Which of the following mineral is incorrectly matched with its chemical formula?
Which test is used to test the significance OF THE DIFFERENCE BETWEEN TWO MEANS?
