The speed of a boat in still water is 32km/hr and the speed of the current is 8km/hr. It takes a total of 15hours to row to upstream from Point A to B and downstream from Point B to C. If the distance between A to C is two-fifth the distance between B and C then what is the distance between B and C? (Where BC < AB)
Let the distance from B to C be xkm ∴ A to C = 2x/5 km Upstream speed = 32 – 8 = 24 km/hr Downstream speed = 32 + 8 = 40km/hr Now, 2x/(5 × 24) + x/40 = 15 2x/120 + x/40 = 15 (2x + 3x)/120 = 15 x = 360 km
√9604 + ∛205379 + 58% of 1500 = 520 + ?
17.8 + 3/7 of 89.6 = ?
Simplify the following expression:
(164-1)/17×15× (28+1)
?= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
(72× 52+ 1555 )/(79+60) = 2000 ÷ ?
√144 × √121 + 25% of 600 = ? + 256
72 x 60 x 22 x 32 =?
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63 × 4 = ?2 – 1620 ÷ 5
