Question
A man can row at 6 kmph in still water. If the velocity
of current is 3 kmph and it takes him 8 hour to row to a place and come back, how far is the place?Solution
Let the distance be x km. Speed upstream = 6 – 3 = 3 kmph Speed downstream = 6 + 3 = 9 kmph => (x/9) + (x/3) = 8 => (x + 3x)/9 = 8 => 4x = 72 => x = 18 km
I. 2x2 - 15x + 25 = 0
II. 3y2 - 10y + 8 = 0
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
If the roots of the quadratic equation 6m² + 7m + 8 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 54x + 704 = 0
Equation 2: y² - 44y + 448 = 0
If x + 1/x = 3, find x² + 1/x².
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 21x² - 122x + 160 = 0
Equation 2: 23y² - 159y + ...
I. 18p²- 21p + 6 = 0   Â
II. 16q² - 24q +9 = 0
I. y² + y – 56 = 0
II. 2x² + 11 x – 40 = 0
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
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