A Passenger boat started its journey from point A to B .After sometime when it is 156 km away from point B it is started to get sinking and passengers found a hole in it from which 10(1/3) ` ` tonnes of water comes in every 26 minutes. But there is a outlet tap which throws out 13 tones of water in every hour. So, find the speed of the boat so that while it is about to sink, another rescue ship which is coming towards it with speed of 14km/hr can save it and 94 tones of water is sufficient to sink that boat ?
In every 26 min, water comes in boat = 31/3 tonnes So in 1 min, water comes in boat = 31/(3*26) tonnes So in 1 hr, water comes in boat = 31*60/(3*26) = 310/13 tonnes and water thrown in 1 hr = 13 tonnes So final water comes in 1 hr = (310/13) - 13 = (310-169)/13 = 141/13 tonnes So it will sink overall in = 94/(141/13) = 26/3 hours So now (x+14) * 26/3 = 156 (as both are in opposite direction, let speed of ship be x kmph) x+14 = 18 x = 4 kmph Speed of ship = 4kmph
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0
