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Let speed of boat in still water and speed of boat in upstream be ‘10x’ km/h and ‘7x’ km/h, respectively. Speed of stream = 10x – 7x = 3x km/h Speed of boat in downstream = 10x + 3x = 13x km/h So, 13x = 390/5 = 78 Or, x = 6 Speed of boat in still water = 10 × 6 = 60 km/h Desired time = 18/60 = 18 minutes
(?)2 + 4.113 = 25.92 – 32.03
12.5% of 6400 + (17 × 25) = ?% of 2200+ 125
85% of 1740 + 30² = ? + 1575 ÷ 15
12.99% of 499.99 ÷ 13.17 = ? ÷ 20.15
(56.04% of 550.06 + 19.92 × 18.13) = ?
( 14.99% of 549.99 ) × 17.02 = ? 2 + 26.02 × 3200 ÷ 800
56.02% of 1499.98 + 64.04% of 2501.01 = ? + 25.05 × 49.98 + 6.063
28.95% of 924.78 + 1955% of 38.99 = ?
√28561.11 × √ 960.9 – (18.02)2 =? × 4.95