Question
The ratio of the speed of boat βAβ in still water,
the speed of boat βBβ in still water and the speed of the current is 11:5:2, respectively. If the time taken by boat βAβ to travel (9D β 26) km downstream is equal to the time taken by boat βBβ to travel (D + 50) km upstream, then find the value of βDβ.Solution
Let, the speeds of boat βAβ and boat βBβ, in still water and the speed of the current be 11x km/hr, 5x km/hr and 2x km/hr, respectively. According to the question, (9D β 26)/(11x + 2x) = (D + 50)/(5x β 2x) Or, 27D β 78 = 13D + 650 Or, 14D = 728 Or, D = 52
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 21xΒ² - 82x + 80 = 0
Equation 2: 23yΒ² - 132y + 85 = 0
Equation 1: xΒ² - 200x + 9600 = 0
Equation 2: yΒ² - 190y + 9025 = 0
Equation 1: xΒ² - 180x + 8100 = 0
Equation 2: yΒ² - 170y + 7225 = 0
I. (y β 5)2 β 9 = 0
II. x2 β 3x + 2 = 0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 41xΒ² - 191x + 150 = 0
Equation 2: 43yΒ² - 191y + ...
Equation 1: xΒ² - 90x + 2025 = 0
Equation 2: yΒ² - 88y + 1936 = 0
I. 3x6- 19x3+16=0
II. 9y4- 27y2+20=0
I. x2 β 39x + 360 = 0
II. y2 β 36y + 315 = 0
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0