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The speed of stream is one fourth of the speed of boat in downstream.
If the speed of stream is 15 km/h.
15 = (¼) of speed of boat in downstream
speed of boat in downstream = 60 km/h
Speed of boat in still water = 60-15 = 45 km/h
The same boat can cover ‘d’ distance in still water in (t-8) hours.
d = 45(t-8) Eq.(i)
The total time taken by a boat to cover (d+30) km in downstream and (d-60) km in upstream is
(t+3) hours.
[(d+30)/60] + [(d-60)/(45-15)] = (t+3)
[(d+30)/60] + [(d-60)/30] = (t+3)
Put the value of ‘d’ from Eq.(i) in the above equation.
[(45(t-8)+30)/60] + [(45(t-8)-60)/30] = (t+3)
[(45t-360+30)/60] + [(45t-360-60)/30] = (t+3)
[(45t-330)/60] + [(45t-420)/30] = (t+3)
[0.75t-5.5] + [1.5t-14] = (t+3)
2.25t-19.5 = t+3
2.25t-t = 19.5+3
1.25t = 22.5
Value of ‘t’ = 18
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