Let’s assume the speed of boat in still water and the speed of stream are ‘B’ and ‘C’ respectively. The speed of the boat in still water is 40% less than the speed of the boat in downstream. B = (100-40)% of (B+C) B = 60% of (B+C) B = 0.6(B+C) If the speed of stream is 16 km/h. B = 0.6(B+16) B = 0.6B+96 B-0.6B = 9.6 0.4B = 9.6 B = 24 km/h The time taken by the boat to cover 468 km distance in upstream is (t+0.5) hours. 468/(t+0.5) = (B-C) Put the value of ‘B’ and ‘C’ in the above equation. 468/(t+0.5) = (24-16) 468/(t+0.5) = 8 468/8 = (t+0.5) (t+0.5) = 58.5 t = 58.5-0.5 Value of ‘t’ = 58
How many members Codex Alimentarius Commission has at present?
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Black soil is use for the cultivation of
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What is the main objective of Pruning?
