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Let’s assume the speed of boat in still water and the speed of stream are ‘B’ and ‘C’ respectively. The ratio between the time taken by a boat to cover a certain distance in upstream and the same distance in downstream is 5:1 respectively. Let’s assume the distance covered in each stream by the boat is ‘d’ km. [d/(B-C)] / [d/(B+C)] = 5/1 (B+C)/(B-C) = 5/1 (B+C) = 5(B-C) B+C = 5B-5C 5B-B = 5C+C 4B = 6C 2B = 3C If the speed of the stream is 60 km/h. 2B = 3x60 = 180 B = 90 The same boat can cover the same distance which was covered in upstream in still water in (35/3) hours. d/90 = 35/3 d/30 = 35 d = 35x30 d = 1050 km The distance covered by the boat in downstream = 1050 km
How many numbers lie between 2000 and 3000 divisible by 5 can be made with the digits 2, 3, 4, 5, 6, 7 and 8 without repeating any digit?
If the sum of two positive numbers is 37 and the difference between these two numbers is 5, then what is the product of the two numbers?
When a number is increased by 20% then the number obtained is 36 less than thrice the original number. Find the original number.
The sum of the digits of a two-digit number is 9. If 27 is subtracted from the number, its digits switch their places. What is the number?
What is the standard deviation of a dataset if its variance is 17.64?
If {p2 + (2p2/5)} = 14p , p ≠ 0, then find the value of {p2 + (10/p) - 1}.
