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Let the speed of boat B in still water be x km/hr. Therefore, the speed of boat A in still water =0.75x km/hr. According to the question, 0.75x + x = 70 Or, 1.75x = 70 Or x = 40 Therefore, the speed of boat B in still water = x =40 km/hr. Speed of boat A in still water = 0.75x = .75×40=30km/hr. Let the speed of the current be ‘y’ km/hr. Downstream speed of boat B = (40 + y) km/hr. Upstream speed of boat A = (30 – y) km/hr. 0.12(40 + y) = 30 – y Or, 4.8 + 0.12y = 30 – y Or, 0.12y + y = 30 – 4.8 1.12y =25.2 y=25.2/1.12=22.5 therefore, speed of the current =22.5km/hr.
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
Find the simplified value of the given expression.
{12.75 × √64 + 13.5 × √(√256)} ÷ 6 + 49.5 ÷ 5.5
(√7225 x √1225)/(√625) = ?
The value of {5 − 5 ÷ (10 − 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
(8.6 × 8.6 + 4.8 × 4.8 + 17.2 × 4.8) ÷ (8.62 – 4.82 ) = ? ÷ 19
390/? = √256 + 3.5
Find the simplified value of the given expression:
224 ÷ 4 + 7 X 36 - 8 of 15 + 162 - 300
2/5 of 3/4 of 7/9 of 7200 = ?
√? + √1296 + √729 = 464/4