The Ship's speed in calm water exceeds that of the current by 20%. After sailing downstream for 4 hours, it traveled upstream for 4 hours with an increased Ship speed of 15 km/h. The Ship covered a distance during downstream travel that is 175% greater than the distance it covered during upstream travel. Determine the original speed of the Ship when moving downstream.
ATQ, Let the speed of the current be ‘a’ km/hr Therefore, speed of the Ship in still water = ‘1.2a’ km/hr Downstream distance travelled by the boat = (a + 1.2a) × 4 = 8.8a km Upstream distance covered by the boat = (1.2a + 15 – x) × 4 = (0.8a + 60) km According to the question, {(8.8a – 0.8a – 60)/(0.8a + 60)} = 1.75 Or, a = (165/6.6) = 25 km/hr Therefore, original downstream speed of the Ship = 2.2a = 55 km/hr
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