A swimmer swims from a point A against a current for 5 minutes and then swims current for next 5 minutes and comes to the point B. If AB is 100meters, the speed of the current is (km/h).
. Let the speed of boat in still water =B and speed of stream =S Distance covered by downstream speed in 5 minutes =(B+S) ×5/60 Distance covered by downstream speed in 5 minutes=(B-S) ×5/60 ATQ- 
S=6/10 =0.6km/h Speed of current =S= 0.6km/h
19.22 × 11.99 + 142.15 = ?
25.22% of (59.9 × 8.01) + 69.97 =?
30.05% of 250.05 – 15.15% of 99.99 × 2.02 = ?
? 2.03 + 121.96 – 55.98 + 129.78% of 59.98 = 399.98
(7.992/√?) + √16/? = 14.032/?
? + 539.76 ÷ 5.4 × 94.80 = 9829.54
16.98 × 88.05 + 1999.996% of 299.08 + 5.005 % of 4999.997 = ? × 20.98 × 40.009
(20.23% of 780.31) + ? + (29.87% of 89.87) = 283
14.2% of 7200 + 2.8% of 6400 =?
