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ATQ, Let the speed of the boat ‘P’ in still water and the speed of the current be ‘p’ km/hr and ‘q’ km/hr, respectively Therefore, downstream speed of boat ‘P’ = (p + q) km/hr Upstream speed of boat ‘P’ = (p – q) km/hr According to the question, {160/(p + q)} = {120/(p – q)} Or, 160p – 160q = 120p + 120q Or, 40p = 280q Or, p:q = 7:1 Therefore, ratio of speed of boat ‘Q’ in still water and the speed of the current = 7:1 Let the speed of the boat ‘Q’ in still water and the speed of the current be 7w km/hr and w km/hr, respectively According to the question, 7w – w = 18 Or, 6w = 18 Or, w = 3 Required time taken = {144/(7w + w)} = 144/24 = 6 hours
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