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ATQ, (p + 40)/48 + (q + 60)/32 = 10 (2p + 80 + 3q + 180)/96 = 10 2p + 3q = 960 – 260 = 700 … (i) Also, (p + 56)/32 + (q + 140)/48 = 13 (3p + 168 + 2q + 280)/96 = 13 3p + 2q = 1248 – 448 3p + 2q = 800 … (ii) Solving equation, (i) and (ii), we get, p = 200 and q = 100 Hence, required sum = (p + q) = 200 + 100 = 300
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