The ratio of the distances traveled by a boat in upstream and downstream is 6:7, respectively, and the total time taken to cover the desired distance is 73 hours. Given that the speed of the current is 40 km/h, which is 8 km/h less than the speed of the boat in still water, determine the distance traveled by the boat upstream.
ATQ, Let the distance covered by the boat in upstream be ‘6a’ km and the distance covered by boat in downstream be ‘7a’ km. Speed of the boat in still water = 40 + 8 = 48 km/h According to question, {(6a/(48 – 40)} + {7a/(48 + 40)} = 73 Or, (6a/8) + (7a/88) = 73 Or, (73a/88) = 73 Or, a = 88 Distance travelled by the boat in upstream = 6a = 528 km
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