ATQ, Let the distance covered by the boat in upstream be ‘6a’ km and the distance covered by boat in downstream be ‘7a’ km. Speed of the boat in still water = 40 + 8 = 48 km/h According to question, {(6a/(48 – 40)} + {7a/(48 + 40)} = 73 Or, (6a/8) + (7a/88) = 73 Or, (73a/88) = 73 Or, a = 88 Distance travelled by the boat in upstream = 6a = 528 km
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