A boat covers a distance of 90 km downstream in 3 hours. If the ratio of upstream speed to downstream speed of the boat is 3:9, then find the distance travelled by the boat in upstream in 6 hours.
ATQ: Let the upstream and downstream speed of the boat be '3x' km/hr and '9x' km/hr, respectively. ATQ, 9x = (90/3) So, 'x' = 3.33 (approx.) So, upstream speed of the boat = 3x = 3 × 3.33 = 9.99 km/hr (approx. 10 km/hr) Required distance = 10 × 6 = 60 km
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