ATQ, Let the upstream speed and downstream speed of the boat be x km/h and y km/h, respectively. So according to question: 80/x + 200/y = 14 ………………. (i) Also, 64/x + 160/y = 10 ……….. (ii) Solving (i) and (ii), we get x = 16 and y = 32 So, the upstream speed and downstream speed of the boat are 16 km/h and 32 km/h, respectively. Speed of the boat in still water = (16 + 32)/2 = 24 km/h Speed of the stream = (32 – 16)/2 = 8 km/h So, the desired difference = 24 – 8 = 16 km/h
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