Continue with your mobile number
For I: Speed of boat = 20 km/h Speed of stream = 7 km/h Speed in upstream = 20 – 7 = 13 km/h Speed in downstream = 20 + 7 = 27 km/h Total time = 200/13 + 300/27 = 15.38 + 11.11 = 26.49 hours So, I can be the answer. For II: Speed of boat = 20 km/h Speed of stream = 8 km/h Speed in upstream = 20 – 8 = 12 km/h Speed in downstream = 20 + 8 = 28 km/h Total time = 200/12 + 300/28 = 16.67 + 10.71 = 27.38 hours So, II can’t be the answer. For III: Speed of boat = 20 km/h Speed of stream = 9 km/h Speed in upstream = 20 – 9 = 11 km/h Speed in downstream = 20 + 9 = 29 km/h Total time = 200/11 + 300/29 = 18.18 + 10.34 = 28.52 hours So, III can’t be the answer. For IV: Speed of boat = 20 km/h Speed of stream = 10 km/h Speed in upstream = 20 – 10 = 10 km/h Speed in downstream = 20 + 10 = 30 km/h Total time = 200/10 + 300/30 = 20 + 10 = 30 hours So, IV can be the answer.
The area of an isosceles triangle ABC is 8√5 cm². In this triangle, sides AB and BC are equal in length, and the base AC has a length of 8 cm. Determ...
A right-angled triangle has an area of 120 m², and the ratio of its base to height is 5:3. The side length of an equilateral tri...
The area of a triangle is 480 cm² and the ratio of its sides is 10: 24: 26. What is the perimeter of the triangle?
In a right-angled triangle, the legs are in the ratio 3:4, and the hypotenuse is 25 cm. Find the perimeter of the triangle.
A triangle XYZ is drawn inside a circle with a radius of 8 cm, such that its vertices lie on the circumference of the circle. Giv...
The smallest side of a right-angled triangle is 7 cm less than the side of a square of perimeter 76 cm. The second largest side of the right-angled tria...
In a triangle ABC, AD is the altitude from A to BC. If AD = 12 cm, AB = 13 cm, and AC = 14 cm, find the length of BC.
In triangle ABC, the lengths of its sides are given as AB = 8 cm, AC = 10 cm, and BC = 12 cm. Determine the length of the median drawn from vertex 'A' t...
The corresponding medians of two similar triangles are 12 cm and 15 cm. If the area of the first triangle is 288 cm, then find the area of the second tr...
In ∆ PQR, S is the midpoint of QR. T is the midpoint of line PS. Then, Area of ∆PTQ : Area of ∆ PQR is