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ATQ, Let, the speed of the boat in still water = 'p' km/h So, the downstream speed of the boat = 1.4p km/h Speed of the stream = 1.4p – p = 0.4p km/h Upstream speed of the boat = p – 0.4p = 0.6x km/h According to question: 66/0.6p + 98/1.4p = 9 110/p + 70/p = 9 p = 180/9, p = 20 So, the time taken by the boat to cover 48 km upstream and 112 km downstream = (48/12) + (112/28) = 4 + 4 = 8 hours
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
I. 4 x ² - 4 x + 1 = 0
II. 4 y ² + 4 y + 1 = 0
...I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 288 = 0
Equation 2: y² - 29y + 210 = 0
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
I). p2 + 17p - 234 = 0
II). q2 - 21q + 108 = 0