Question
A boat travels 40 km downstream in 5 hours, and the same
boat travels 40 km upstream in 8 hours. Find the speed of the boat in still water.Solution
Let the speed of the boat in still water be x km/h, and the speed of the stream be y km/h. Downstream speed = (x + y) km/h, and upstream speed = (x - y) km/h. Downstream: 40 / (x + y) = 5 Upstream: 40 / (x - y) = 8 From the downstream equation: x + y = 40 / 5 = 8. From the upstream equation: x - y = 40 / 8 = 5. Now solve: x + y = 8 x - y = 5 Adding both equations: 2x = 13 x = 6.5 km/h Thus, the speed of the boat in still water is 6.5 km/h.
If cosx/siny = n and cosx/cosy = m, then the value of cos 2 y is:
1. m 2 /(m 2 + n 2 )
2. 1/(m ...If 2ycosθ = x sinθ and 2xsecθ – ycosecθ = 3, then x 2 + 4y 2 = ?
The angle of depression of two ships from the top of a light house are 45º and 30º. if the ships are 120m on the opposite sides of lig...
sin2 7 ° + sin2 8 ° + sin2 9 ° + sin2 10 ° + ……… + sin2 83 ° = ?
...If (tan 8θ · tan 2θ = 1), then find the value of (tan 10θ).
If sin(x + y) = 1 and sin(x - y) = (1/2), then what is the value of sinx cosx + 2sin2y + cos2y?
if a sin 45 ˚ = b cosec 60 ˚ then find the value of a⁴/b⁴
...If cot5A = tan(3A-14˚), find the value of A? Given that 5A and 3A-14˚ are acute angles.
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, then determine the value of (4A - B).
Given that tan(A+B) = √3 and tan(A-B) =1/√3, find the values of A and B.