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Let the speed of boat in still water and speed of stream be 'v' and 'x' km/h respectively. ATQ, x:(v - x) = 1:9 Or, 9x = v - x Or, 'v' = 10x -------- (I) Downstream speed = v + x = 10x + x = '11x' km/h So, 11x = (82.5/2.5) Or, 11x = 33 So, 'x' = 3 On putting value of 'x' in equation (I) , We get, 'v' = 10 X 3 = 30 Therefore, required time = (54/30) = 1.8 hours = 1.8 X 60 = 108 minutes
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