Question
A boat takes 20 hours to travel 260 km downstream. The
speed of the boat in still water is 125% greater than the speed of the stream. If the boat completes a round trip from point 'P' to point 'Q' and back to 'P' in 18 hours, determine the distance between points 'P' and 'Q'.Solution
Downstream speed of the boat = (260/20) = 13 km/hr Let the speed of the stream be '4x' km/hr So, speed of boat in still water = 4x X (2.25) = '9x' km/hr So, (4x + 9x) = 13 So, 13x =13 So, 'x' = 1 So, speed of the boat in still water = 9 km/h The upstream and downstream speed of the boat are 5 km/h and 13 km/h respectively. Let the distance between points 'P' and 'Q' be 'A' km. ATQ, (A/13) + (A/5) = 18 Or, (18A/65) = 18 So, 'A' = 65
(1550.23 ÷ 30.98) + (864.32 ÷ 23.9) + 1724.11 = ?
? = 21.91% of (36.2 × (144.01 + 5.95)) + 16.71
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(12.13) 2 - 19.93 + 39.78 - 42.93 = ?
(6859.01)1/3 × 10.11 × 14.47 ÷ 20.32 = ? + 45.022
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(29.98% of 9840) + ? + (19.899% of 8490) = 7560
Bijay can complete a task on his own in 40 days, while Ajay can finish the same task in 25 days. If they alternate working on the...
– (8.002)³ + (30.001)² - (4.01)⁴ =?
31% of 3300 +659 = ?
Relevant for Exams:
