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ATQ, Let the speed of the stream while going downstream = ‘2a’ m/s So, the speed of the stream while the boat is going upstream = 50% of ‘2a’ = ‘y’ m/s Since the ratio of time taken by the boat to go a certain downstream distance to that taken to come back is 4: 5. So, the ratio of downstream speed to the upstream speed of the boat = 5: 4 (13 + 2a)/(13 – a) = 5/4 52 + 8a = 65 – 5a a = 1 Speed of stream while boat is going downstream = 2 × 1 = 2 m/s Downstream speed of the boat = 13 + 2 = 15 m/s So, downstream distance covered by the boat in 24 seconds = 15 × 24 = 360 m
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