A man rows upstream 10 km and downstream 15 km taking 5 hours each. Find the man’s speed in still water.
Distance upstream = 10 km, time taken to row upstream = 5 hrs. Speed upstream = 10/5 = 2 km/hr. Distance downstream= 15 km, Time taken to row downstream = 5 hrs. Speed downstream = 15/5 = 3 km/hr. Man’s rate in still water = (3 + 2) * ½ = 2.5 kmph
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
766/51 ÷ 387/42 × 121/13 = ?
648.13 ÷ 35.86 + 28.88 × 13.13 – 39.92% of 900.19 = ?
1359.98 ÷ 20.48 × 12.12 = ? × 4.16
? (30.03 - 17.98 × 15.99 ÷ 12.01) = 729.03
124% of 620.99 + 11.65% of 1279.23 = ?
480.11 ÷ 15.98 × 5.14 – 134.9 = √?
Solve the following expression and calculate the approximate value.
802 of
{44.78% of (11.67 × 54.78)} ÷ 2.65 = ? + 19.25
3.55% of 8120 – 66.66% of 540 = ? – 28% of 5500
