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Let us consider the three positive numbers as x, y and z. Sum of three positive numbers x + y + z = 18 ---------> (1) product of three numbers xyz=162 ----------> (2) Given that sum of two numbers is equal to the third. i.e.., x + y = z => 2z = 18 => z = 9 Replacing z=9 in equation (1) & (2), we get x + y = 9 and xy = 18 Solving above, we get x = 6 and y = 3 therefore, sum of squares of the numbers = 62 + 32 + 92 = 126
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