How many students appeared in exam X or in exam Z?
Total students = 1000 Let, students appear in exam Z only = a Total students appeared in exam Y = 360 Ratio of number of students appeared in exam X and Y only to students appeared in exam Y and Z only = 2:3 Students appeared in exam X and Z both = a/2 Number of students appeared in all three exams = (4/100) × 1000 = 40 Number of students appeared in Y exam only = No. of students appeared in Y and Z only = 3x Number of students appeared in exam X and Y only = (2/3) × 3x = 2x Now, 2x + 3x + 3x + 40 = 360 ⇒ x = 40 And, 12.5x + a + a/2 + a = 1000 => 5a/2 = 500 ⇒ a = 200 
Students appeared in exam X or in exam Z = 180 + 60 + 40 + 80 + 200 + 120 = 680
96% of 4500 – 34% of 650 = ?
5555 ÷ 11 ÷ 5 = 100 + ?
154 × 7 + 480 × 5 = ?% of 6956
35% of 840 + 162 = ? – 25% × 300
Simplify: (23×32) ÷6
?3 - 25 × 11 = 30 - 15 × 12
(3333 ÷30) + (785 ÷25) + (2981 ÷11) = ?
5.45% of 1854 – 37.5% of 1096 = ? – 48% of 630
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
