Question
Number of male employees who are married is how much
percent more/less than number of female employees who are unmarried? Study the following information carefully and answer the given questions: There are total 840 employees (male + female) in company ‘XYZ’. There are two types of categories married and unmarried employees. 120 male employees are married which is 30% of total male (married + unmarried) employees. Difference between number of male and female employees who are unmarried is 180.Solution
Total number of male employees who are married = 120 Total number of male employees (married + unmarried) = (120/30) × 100 = 400 Number of male employees who are unmarried = 400 − 120 = 280 Total number of female employees = 840 − 400 = 440 Total number of female employees who are unmarried = 280 − 180 = 100 Number of female employees who are married = 440 − 100 = 340 Required % = [(120 – 100)/100] × 100 = 20%
((0.1)3+ (1.8)3+ (1.1)3 - 0.3 ×1.8 ×1.1)/((0.1)2+ (1.8)2+ (1.1)2- (0.18)- ...
180 % of 45 + √144 × 8 = ?2  + 80 % of 70
Find the simplified value of the given expression.
(1/4) of {64Â - 28 x 15 + 13 x 16 - 12.5 of 122}
If x²y² + (1/ (x2y2)) = 83, then the value of xy – 1/xy is:
32% of 450 + 60% of 150 = ? × 9
What is the value of ‘x’ if x% of 720 added to {2160 ÷ x of 20} × 2 gives 180?
Find the value of the following expression:
372 ÷ 56 × 7 – 5 + 2
(1/5){(2/5) × 400 + 20% of 150} = ?Â
1280 ÷ 8 + 490 ÷ √49 + ? = 150 * 2
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