Question
Study the given graph and answer the question that
follows. Break up for distribution (degree wise) of the employees working in five departments (A, B, C, D and E) in a company.  The total number of employees working in departments A and C exceeds the total number of employees working in departments B and D by x. The value of x lies between:Solution
Total number of employees in department A and B = 79.2° + 57.6° = 136.8° Total number of employees in department C = 122.4° Number of employees in A and B is more than that of C by = 136.8° – 122.4° = 14.4° Number of employees in A and B is more than C by = 3200 × 14.4/360 = 128 As we know, 128 lies between 120 and 140.
What is the length of the hypotenuse in an isosceles right-angled triangle if one of its equal sides measures 6√2 cm?
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A â–³ ABC has sides 5 cm, 6 cm and 7 cm. AB extended touches a circle at P and AC extended touches the same circle at Q. Find the length (in cm) of AQ.
If the side of an equilateral triangle is 12cm, then find the area (in cm 2 ) of the triangle (correct to two decimal places).
The base of an isosceles triangle is 20 cm, and the sum of the other two sides is 30 cm. Find the area of the triangle.
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In a right-angled triangle, the hypotenuse is 20 cm, and one of the legs is 12 cm. Find the area of the triangle.
∠A, ∠B, and∠C are three angles of ∆ABC.if ∠A-∠B=15°, ∠B-∠C =30°,then ∠A, ∠B and ∠C are?
What is the height of an equilateral triangle with a side length of 10√2 cm?
Find the hypotenuse of an isosceles right-angled triangle where each of the equal sides is 7√5 cm.
