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Total number of male employees in the company = 640 Let the number of male employees in HR department be x. Now, number of male employees in IT department = x – 10 Number of male employees in Marketing department = x – 20 Number of male employees in Production department = x – 30 According to question, => x + x – 10 + x – 20 + x – 30 = 640 => 4x = 640 + 60 => x = 175 So the number of male employees in HR department = 175 Number of male employees in IT department = 165 Number of male employees in Marketing department = 155 Number of male employees in Production department = 145 Number of female employees in Marketing department = 145 Number of female employees in IT department = 160 Number of female employees in HR department = 160 × (7/8) = 140 Number of female employees in Production department = 160 × (5/8) = 100 Required average = (120 + 150 + 120)/3 = 390/3 = 130
One of the roots of the equation p2 - (y+3)p + 6y = 0 is cube of 2. What will be the difference of other root and 'y'.
I. 6x2 + 19x + 10 = 0
II. y2 + 10y + 25 = 0
I. 3x2 – 17x + 10 = 0
II. y2 – 17y + 52 = 0
I. 12x2 + 22x + 8 = 0
II. 4y2 - y − 3 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
I. x2 - x - 56 = 0
II. y2 - 20y + 96 = 0
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I. x ² + 5 x + 6 = 0
II. y²+ 7 y + 12= 0
...I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I). p2 - 20p + 51 = 0,
II). 2q2 - 7q + 6 = 0