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Let the number of teachers in school A = 5x Then the number of boys in school A = 7x According to the question, => 5x + 7x = 84 × 2 => x = 14 So, number of teachers in school A = 5 × 14 = 70 Number of boys in school A = 7 × 14 = 98 Number of girls in school B = 84 × (9/7) = 108 Number of girls in school C = 140 – 108 = 32 Number of boys in school C = 98 + 2 = 100 Number of teachers in school B = 168 × (13/24) = 91 Number of boys in school B = 168 – 91 = 77 Number of teachers in school C = 91 + 11 = 102 Number of boys in school C = 98 + 2 = 100 
Required average = (98 + 100)/2 = 99
7, 14, 42, 210, 1470, ?
362 284 393 451 144 221
...5, 11, 19, 29, 41, ?
Select the number from among the given options that can replace the question mark (?) in the following series.
24, 35, 51, 73, 102, ?
7 98 644 3145 12596 37797
...2, 12, 36, 80, ?, 252
43 ? 45 39 47 37
...9 49 251 ? 2999 5989
...3, 4, 10, 33, 136, ?, 4116
If 24 33 x 42 6 51
Then, 20% of x + 40% of x=?
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