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Milk Water P1 A 5x 2x - B 2y - y C - 2x Vessel A, => 5x + 2x = 28 => x = 4 Quantity of milk in vessel A = 5x = 20 Quantity of water in vessel A = 2x = 8 Quantity of milk in vessel B, => 2y + 20 = 40 => y = 10 litres Quantity of milk in vessel B = 20 litres Quantity of P1 in vessel C = (1500/60) = 25 litres Now, ratio of quantities of mixture in B and C is 6:13. => 30/C = 6/13 => C = 65 Quantity of mixture in C = 65 litres So, 2x + 25 = 65 => 2x = 40 litres Quantity of milk in vessel A = 40 litres Quantity of water in vessel A = 100 litres Required % = [(40 – 10)/10] x 100 = 300%
18 × √225 + 378 ÷ √441 = ? × 9
x= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
√? + √1296 + √729 = 464/4
Evaluate: (768÷16)×(125÷25)−(81÷9)×12
15.8% of 9000 + 20.4% of 7500 = 30% of ?
`(450 -: ?)/(2.5 xx 1.2)` = 250
(15 × 16) + 242= ? × 16
(43)² - (28)² + (32)² = ?% of 2500
Find the HCF of 15x2 + 8x – 12, 3x² + x – 2, 3x² - 2x, 9x² - 12x + 4