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Let the number of girls participated from school B and number of boys participated from school C = x Let number of boys and girls participated from school A be 2y and 3y respectively. According to question, => 2y + 3y = 180 => y = 36 Number of boys from school A = 2y = 72 Number of girls from school A = 3y = 108 Number of girls participated from school C = 3y – 18 = 90 Now, 100 + x + x + 90 = 490 => 2x = 300 => x = 150 Number of girls participated from school B and number of boys participated from school C = 150 Required ratio = 72 : 90 = 4:5
7, 14, 42, 210, 1470, ?
362 284 393 451 144 221
...5, 11, 19, 29, 41, ?
Select the number from among the given options that can replace the question mark (?) in the following series.
24, 35, 51, 73, 102, ?
7 98 644 3145 12596 37797
...2, 12, 36, 80, ?, 252
43 ? 45 39 47 37
...9 49 251 ? 2999 5989
...3, 4, 10, 33, 136, ?, 4116
If 24 33 x 42 6 51
Then, 20% of x + 40% of x=?
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