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Let the number of girls participated from school B and number of boys participated from school C = x Let number of boys and girls participated from school A be 2y and 3y respectively. According to question, => 2y + 3y = 180 => y = 36 Number of boys from school A = 2y = 72 Number of girls from school A = 3y = 108 Number of girls participated from school C = 3y – 18 = 90 Now, 100 + x + x + 90 = 490 => 2x = 300 => x = 150 Number of girls participated from school B and number of boys participated from school C = 150 Number of boys participated from school B and C together = 100 + 150 = 250 Required % = (180/250) x 100 = 72%
385! In the trailing Zeros, let us know.
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