Total apples sold by ‘P’ = 1080/1.20 = 900 Green apples sold by ‘P’ = (900 – 100)/2 = 400 Red apples sold by ‘P’ = 900 – 400 = 500 Green apples sold by ‘Q’ = 3/2 × 400 = 600 Red apples sold by ‘Q’ = 1080 – 600 = 480 Red apples sold by ‘R’ = 0.80 × 480 = 384 Green apples sold by ‘R’ = 384/1.50 = 256 Total apples sold by ‘R’ = 256 + 384 = 640 Total apples sold by ‘S’ = 680 × 2 – 640 = 720 Green apples sold by ‘S’ = 5/12 × 720 = 300 Red apples sold by ‘S’ = 7/12 × 720 = 420 Number of Red apples sold by ‘P’ and ‘Q’ together = 500 + 480 = 980 Number of Green apples sold by ‘R’ and ‘S’ together = 256 + 300 = 556 Required difference = 980 – 556 = 424
(1280.23 ÷ 31.98) + (912.32 ÷ 23.9) + 1864.11 = ?
5983.987 + 59832.999 – 598.873 = ?
(56.04% of 550.06 + 19.92 × 18.13) – 121.97 = ?
5999.93 ÷ 60.005 × 70.002 = ? × 24.9
647.1 ÷ ? + 72.3 × 209.81 – 8743.1 = 6404
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
(?)2 + 4.113 = 24.92 – 32.03
Two trains, 'P' and 'Q', are moving with speeds of 16 m/s and 24 m/s, respectively. The lengths of the trains are in the ratio 3:...
? = 23.08 + 19.99 × 28.07
390.11 ÷ 12.98 × 5.14 – 119.9 = √?