Let number of Turkey burger sold by Kalsang, Farzi and Piccolo be 15x, 10x and 4x respectively. Let number of Bean burger sold by Kalsang = ‘y’= number of Bean burger sold by Piccolo Number of Veggie burger sold by Kalsang = (10 + y) According to question, => 15x +10x + 4x = 15x + (10 + y) + y => 29x = 15x + 10 + 2y => y = 7x – 5 ------- (i) Let number of Bean burger sold by Farzi be ‘a’. So, (y + a + y)/3 = 160/3 => 2y + a = 160 ------- (ii) Number of Veggie burger sold by Piccolo = (a/2) = 0.5a Let number of Veggie burger sold by Farzi = b Total number of Veggie burger sold = 160 – 40 = 120 => (10 + y) + b + 0.5a = 120 => y + b + 0.5a = 110 ------- (iii) b : 4x = 5 : 4 => b = 5x ------- (iv) Solving (i), (ii), (iii) and (iv) we get, => x = 6, y = 37, a = 86 and b = 30 
Required difference = (30 + 43) – 24 = 49
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