Question
In café ‘XYZ’, total number of Turkey burgers sold
is 20% less than total number of Bean burgers sold by all the three cafes. Find the number of Turkey burgers sold by ‘XYZ’. Read the following data carefully and answer the questions: Three different cafes Kalsang, Farzi and Piccolo offers three types of burgers i.e Turkey burger, Veggie burger and Bean burger. The ratio of number of Turkey burgers sold by Kalsang, Farzi and Piccolo is 15:10:4 respectively. Veggie burger sold by Kalsang is 10 more than that of Bean burger sold by Piccolo and Turkey burger sold by all the three cafes is equal to the total number of burgers sold by Kalsang. Number of Bean burger sold by Kalsang is same as sold by Piccolo. The average number of Bean burgers sold by all the cafes is (160/3) and Veggies burger sold by Piccolo is half of the number of Bean burgers sold by Farzi. Total number of Veggie burgers is 40 less than the total number of Bean burgers sold by all the cafes. The ratio of number of Veggies burgers sold by Farzi to the number of Turkey burgers sold by Piccolo is 5:4.Solution
Let number of Turkey burger sold by Kalsang, Farzi and Piccolo be 15x, 10x and 4x respectively. Let number of Bean burger sold by Kalsang = ‘y’= number of Bean burger sold by Piccolo Number of Veggie burger sold by Kalsang = (10 + y) According to question, => 15x +10x + 4x = 15x + (10 + y) + y => 29x = 15x + 10 + 2y => y = 7x – 5 ------- (i)  Let number of Bean burger sold by Farzi be ‘a’. So, (y + a + y)/3 = 160/3 => 2y + a = 160 ------- (ii) Number of Veggie burger sold by Piccolo = (a/2) = 0.5a Let number of Veggie burger sold by Farzi = b Total number of Veggie burger sold = 160 – 40 = 120 => (10 + y) + b + 0.5a = 120 => y + b + 0.5a = 110 ------- (iii) b : 4x = 5 : 4 => b = 5x ------- (iv) Solving (i), (ii), (iii) and (iv) we get, => x = 6, y = 37, a = 86 and b = 30 
Total number of Turkey burgers sold by ‘XYZ’ = 80% of 160 = 128
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