In café ‘XYZ’, total number of Turkey burgers sold is 20% less than total number of Bean burgers sold by all the three cafes. Find the number of Turkey burgers sold by ‘XYZ’.
Let number of Turkey burger sold by Kalsang, Farzi and Piccolo be 15x, 10x and 4x respectively. Let number of Bean burger sold by Kalsang = ‘y’= number of Bean burger sold by Piccolo Number of Veggie burger sold by Kalsang = (10 + y) According to question, => 15x +10x + 4x = 15x + (10 + y) + y => 29x = 15x + 10 + 2y => y = 7x – 5 ------- (i) Let number of Bean burger sold by Farzi be ‘a’. So, (y + a + y)/3 = 160/3 => 2y + a = 160 ------- (ii) Number of Veggie burger sold by Piccolo = (a/2) = 0.5a Let number of Veggie burger sold by Farzi = b Total number of Veggie burger sold = 160 – 40 = 120 => (10 + y) + b + 0.5a = 120 => y + b + 0.5a = 110 ------- (iii) b : 4x = 5 : 4 => b = 5x ------- (iv) Solving (i), (ii), (iii) and (iv) we get, => x = 6, y = 37, a = 86 and b = 30 
Total number of Turkey burgers sold by ‘XYZ’ = 80% of 160 = 128
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