A circle touches all four sides of a quadrilateral. If AB = 18 cm, BC = 21 cm, and AD = 15 cm, then what is the length of CD?
Let length of CD = x When all four sides of a quadrilateral touch a circle, then the opposite sides of that quadrilateral are equal. Then -AD +BC = AB +CD 15 +21 = 18 + x 18 + x = 36 X = 18cm 
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